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6x^2+48x-296=0
a = 6; b = 48; c = -296;
Δ = b2-4ac
Δ = 482-4·6·(-296)
Δ = 9408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9408}=\sqrt{3136*3}=\sqrt{3136}*\sqrt{3}=56\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-56\sqrt{3}}{2*6}=\frac{-48-56\sqrt{3}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+56\sqrt{3}}{2*6}=\frac{-48+56\sqrt{3}}{12} $
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